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2014-05-20T22:16:31+03:00
ΔABC, mas<A=90 ⇒BC²=AB²+AC²= 20²+15²= 400+225=625   ⇒BC=25

AD-h

AD=AB*AC/BC=  20*15/25=  20*3/5= 4*3=12 
2014-05-20T22:16:39+03:00


ip²=20²+15²

ip²=400+225

ip²=625

ip=√625

ip=25

h=20*15/25

h=12

sper ca te-am ajutat

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