Răspunsuri

2014-05-20T22:18:55+03:00
1) ⇒2x-4≤6x-3-2
2x-6x≤4-5
-4x≤-1     ·(-1)
x≥1/4
x∈[ 1/4, +α)
2)⇒(4-√3)x≤-4+√3
x≤-(4-√3)/(4-√3) se simplifica
x≤-1
x∈(-α, -1]
3)⇒√2x-3√2x≤-8+2
-2√2x≤-6         ·(-1)
x≥6/2√2 simplificam
x≥3/√2 rationalizam
x≥3√2/2
x∈[3√2/2, +α)