Răspunsuri

2014-05-19T12:32:46+03:00
Media geometrica √a*b, ambele sub radical. Cum modulele se inmultesc rezulta ca a*b=|(4√5-9)*(4√5+9)|=|16*5-9*9|= |80-81|=|-1|=1 rezulta ca media geometrica =√1=1
2014-05-19T14:47:59+03:00
Mg=√a*b,  
Mg= a*b=|(4√5-9)*(4√5+9)|=|16*5-9*9|= |80-81|=|-1|= =√1=1
Succes!