A+b+c+d=120 sa se afle a,b ,c si dstiind ca a+5,d-5, c:5, dx5 numere egale

1
5d=a+5
5d=a+5 d=a+5/5 c/5=a+5 c=5a+25 a+5=b-5 a+5=b a+a+5+5a+25+a+5/5= 120 7a+30+a+5/5=120 7a+a+5/5=120-30
35a+a+5=90x5

Răspunsuri

2014-05-18T23:56:06+03:00
a+b+c+d=120 sa se afle a,b ,c si d stiind ca a+5,b-5, c:5, dx5 numere egale

daca 
a+5,b-5, c:5, dx5 sunt numere egale =>  a+5 = b-5 = c:5 = dx5 = 120/4 = 30 (pt ca a + b + c + d = 120) =>
a+5 = 30 => a = 30-5=25
b-5 = 30 => b = 30+5=35
c:5 = 30 => c = 30x5 = 150
dx5 = 30 => d = 30/5 = 6