Răspunsuri

2014-01-25T13:56:18+02:00
15/(2x-3) ∈ Z <=> (2x-3) divide pe 15 => (2x-3) ∈ divizorilor lui 15 {1,3,5,15,-1,-3,-5,-15}

Se calculeaza fiecare in parte : 
2x-3=1 => x=2
2x-3=3 => x=3
2x-3=5 => x=4
2x-3=15 => x=9

2x-3= -1 => x=1
2x-3= -3 => x=0
2x-3= -5 => x=-1
2x-3=-15 => x=-6
2 5 2