Răspunsuri

2014-01-25T13:48:25+02:00
Delta= b^2-4ac
delta= 16-4*6*2
delta=16-48<0 => 2x^2+4x+6>0 oricare ar fi x apartine R 
2014-01-25T13:49:28+02:00
 2x^{2} +4+6>0&#10; 2x^{2}>-4-6&#10; 2x^{2}>-10&#10; x^{2}>- \frac{10}{2} &#10; x^{2}>-5
2x la a doua +4+6>0
2x la a doua >-4-6
2x la a doua >-10
x la a doua > - 10 supra 2
x la a doua :> - 5