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Cel mai inteligent răspuns!
2014-01-24T17:12:38+02:00
3 numere a, b, c se afla in progresie geometrica, atunci b²=a*c
deci 4²=x(x-6)
=> x²-6x-16=0
Se rezolva ecuatia de gradul 2:
Δ=36-4*1*(-16)=36+64=100
x1=(6-√100)/2=6-10)/2=-4/2=-4 <0
x2=6+√100)/2=16/2=8 >0

Deci x=8 >0
1 5 1