Răspunsuri

2014-05-15T22:48:38+03:00
Se rationalizeaza numitorii
√3(6-√6)/6*3= (6√3-√18)/6*3= (6√3-3√2)/6*3= 3(2√3-√2)/6*3=  (2√3-√2)/6

√2(4+3√6)/3*2= (4√2 +3√12)/3*2= (4√2+6√3)/3*2= 2(2√2+3√3)/3*2= (2√2+3√3)/3

√3(√6-2)/4*3=(√18-2√3)/4*3= (3√2-2√3)/12

√5(3+√6)/2*5= (3√5+√30)/10  

(2√3-√2)/6 - (2√2+3√3)/3 - (3√2-2√3)/4- (3√5+√30)/10  aducem la acelasi numitor
20√3-10√2-40√2 -60√3 -45√2 + 30√3 -18√5 + 6√30
-10√3 -95√2 -18√5 +6√30
1 5 1