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2014-05-15T18:05:18+03:00
NaOH + H2O ---> <--- NaO- + H3O+
40 g NaOH.....19 g H3O+
4 g NaOH........x g H3O+         x = 1,9 g H3O+
cM=nr moli/volum=masa H3O+/masa molara H3O+ * volumul
cM=1,9/19*1=>cM=0,1 moli/litru=>[H3O+]=0,1 moli/litru
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