Răspunsuri

2014-05-14T20:19:48+03:00
A+b+c=118
b+c=70
a=118-70
a=48

a=3b
b=a/3
b=48/3
b=16

c=70-16
c=54
a+b+c=188
b+c=70
a=118-70
a=48

b=48:3
b=16

c=70-16
c=54
la c am facut 70-16 pt ca b+c =70
a+b+c=118
b+c=70; rezulta a+70=118 ;a=118-70 ;a=48; b=48:3; b=16; c=70-16; c=54.
2014-05-14T20:23:07+03:00
A + b + c = 118
b+c = 70
a = 3b
Inlocuim in prima
3b + 70 = 118 => 3b = 118-70 =>3b=48/:3 => b = 16
c il scoatem din a 2 relatie
16 + c = 70 => c = 70-16 => c = 54
Inlocuim in prima relatie
a + 16 + 54 = 118 => a = 118 - 16 - 54 => a =  48
Bafta !