Răspunsuri

2014-05-12T19:42:48+03:00
Notam cu O intersectia diagonalelor BD, AC
ΔAOD
 DO≡AO⇒ A≡D  A+D+O=180⇒A=D=60⇒ΔAOD Δechilateral⇒AD=45
ΔADB Δdreptunghic⇒BD²=AD²+AB²⇒AB²=BD²-AD²⇒AB=45√3
A=Lxl=45√3x45=2015√3
P=2(L+l)=2(45√3+45)=90(√3+1)
1 5 1