Răspunsuri

2014-05-11T22:59:54+03:00
4x²+12x+9>4x²+10x+1
2x>-8, x>-4, x∈(-4, +infinit)

x²+x-6≥x²-4x+4
5x≥10, x≥2, x∈[2, +infinit)

4x²+5x<4x²-4x+1+8
9x<9, x<1, x∈(-infinit, 1)

x²+6x+9<x²-2x+1+24
8x<16, x<2, x∈(- infint, 2)