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2014-05-12T14:44:50+03:00
NaNO3-azotat de sodiu
Masa molara NaNO3=1*23+1*14+3*16=23+14+48=85g
85gNaNO3...................23gNa..............14gN..............48gO
100gNaNO3.................x.......................y....................z
x=23*100/85=27.05%
y=14*100/85=16.47%
z=48*100/85=56.47%
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