Răspunsuri

2014-05-11T12:13:59+03:00
(x-1)(x-1)²-3x+3-4
(x-1)(x²-2x+1)-3x-1
x³-2x²+x-x²+2x-1-3x-1
x³-3x²-2=0
x³-x²-2x²-2=0
x²(x-1)-2(x-1)=0
(x-1)(x²-2)=0
x-1=0   x²-2=0
x=1       x²=2   
             √x²=√2
               |x|=√2   ⇒x∈{-√2; √2}