Răspunsuri

2014-05-10T00:42:06+03:00
X²-8x+15= x²-3x-5x+15= x(x-3)-5(x-3)= (x-3)(x-5)

[(2x-8)/(x-3)(x-5) - 1/x-3 ] : 1/ (x-5)(x+5)   aducem la acelasi numitor in[ ]

[(2x-8)-(x-5)] /(x-3)(x-5)  :1/(x-5)(x+5)
(2x-8-x+5) /(x-3)(x-5)  : 1/ (x-5)(x+5)
(x-3)/ (x-3)(x-5) : 1/ (x-5)(x+5)
1/(x-5)  * (x-5)(x+5)/1=  x+5


2 3 2