Răspunsuri

2014-05-09T21:31:04+03:00
Q=mcΔT⇒m=Q/cΔT
c=4180J/KgK caldura specifica a apei
m= 2 kg, 
ρ=m/V⇒V=m/ρ=2/1000=0.002  m^{3}