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2014-05-09T12:26:53+03:00
Md=ms*c/100=200*40/100=80 g
2 CH3COOH + CaCO3 ----> (CH3COO)₂Ca + H2O + CO2
2 * 60 g acid.........22,4 l CO2 
80 g acid...............x l CO2          x = 14,93 litri CO2
V in cond normale = 22,4 litri;masa acid = 60g/mol=4+24+32
9 2 9