Răspunsuri

2014-01-22T16:44:15+02:00
 si mie mia iesit la fel solutia ca primul raspuns
2014-01-22T16:48:33+02:00
Eu cred ca e: a)f'(x)=(lnx)'=1/x => f'(x0)=f'(1)=1/1=1; b) f'(x)=(cosx)'=-sinx=>f'(x0)=f'(1)=-sin(1)