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2014-05-08T17:01:58+03:00
1)m(A)+m(B)+m(C)=180, 90+60+m(C)=180=>m(C)=30
sinB= \frac{AC}{BC} =>BC= \frac{AC}{sinB}= \frac{8 \sqrt{3} }{ \frac{ \sqrt{3} }{2} }=16

cosB= \frac{AB}{BC}=>AB=BC*cosB=16* \frac{1}{2}=8


2)sinC= \frac{1}{2}=>m(C)=30
m(A)+m(B)+m(C)=180,  
90+30+m(B)=180=>m(B)=60
cosC= \frac{AC}{BC}=>BC= \frac{AC}{cosC} =   \frac{3}{ \frac{ \sqrt{3} }{2} }   =2 \sqrt{3}

tgC= \frac{AB}{AC}=>AB=AC*tgC=3* \frac{ \sqrt{3} }{3} = \sqrt{3}
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