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2014-05-07T21:25:56+03:00
C%=md/ms*100=>md HNO3=300*21/100=63 g HNO3
NaOH + HNO3 ---> NaNO3 + H2O
40 g NaOH.......63 g HNO3
x g NaOH..........63 g HNO3       x = 40 g NaOH = md NaOH
%apa=60%=>100 g solutie.........60 g apa =>m apa = 60 g
ms = m apa + md = 40+60=100 g
c%=md/ms*100=40/100*100=40 %
Reactia este mol la mol=> din 40 g NaOH sau 63 g HNO3 se obtin 18 g apa (folosesti masele molare)