Răspunsuri

2014-01-21T22:00:54+02:00
Cos23π/12 x sin π/12=cos(2π-π/12) x sin π/12 =cos(π/12) x sin (π/12)=
(1/2)sin(π/6)=(1/2)(1/2)=1/4
imi poti explica , te rog cum ai ajuns de la cos23π/12 la cos(2π-π/12)
23pi/12=24pi/12-pi/12=2pi-pi/12
foloseste si formulele: cos(2pi+x)= cos (x) si cos (x)=cos(-x)
am inteles acum , multumesc mult :)