Răspunsuri

2014-05-07T15:36:06+03:00
[(n+260:2) x 3 +4]= 1985:5=397
[( n+130) x3+4]= 397
(n+130) x3 +4 =397
(n+130 ) x 3= 397-4= 393
n+130= 393:3= 131
n= 131-130
n=1
3 4 3
2014-05-07T15:39:12+03:00
[(n+260:2) x3 +4]x5=1985
(n+130x3+4)x5=1985
(n+390+4)x5=1985
Paranteza o notam cu a :
ax5=1985
a=1985:5=397
si apoi zicem
n+390+4=397
n+394=397
n=497-494
n=3

1 5 1