Răspunsuri

2014-05-06T00:17:45+03:00
253=\pi R(G+R)
11=\pi R G

Inlocuim a doua relatie in prima

253=11+\pi \ R^2
242=\pi R^2

R=\sqrt{\dfrac{242}{\pi}}=\dfrac{11\sqrt2}{\sqrt{\pi}} Inlocuim in al doilea rand de sus

G=\dfrac{11}{\pi R}=\dfrac{11}{\pi\cdot\dfrac{11\sqrt2}{\sqrt{\pi}}}=\dfrac{1}{\sqrt{2\pi}}=\dfrac{\sqrt{2\pi}}{2\pi}

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