Răspunsuri

2014-05-06T02:28:07+03:00
ΔABC, mas<A=70,  mas<C=30   ⇒mas<B=180-70-30=80
BM-bisect<ABC
mas<ABM=mas<MBC=mas<B/2=80/2=40
fie BD_|_AC
BD-h    
ΔBDC, mas<D=90, mas<C=30   ⇒mas<CBD=180-90-30=60
mas<ABD=mas<B-mas<CBD=80-60=20

mas<DBM=mas<ABM-mas<ABD=40-20=20  
 ⇒mas<(bisect<B, inaltimea ce pleaca din B)=mas<DBM=20
4 3 4