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2014-05-05T21:12:46+03:00
CM=c%*ro*10/masa molara HCl respectiv NaOH
a)cM=0.3*1.15*10/36.5=0,09452 moli/litru
pH=-lg[HCl]=-lg 0,09452 =>pH = 1.0245
b)cM=0.0392*1.02*10/40=0,01 moli/litru
pOH=-lg[NaOH]=-lg 0.01 => pOH = 2