Răspunsuri

2014-05-04T15:50:06+03:00
A) 2x+a=0 are ca solutie -5 <=> 2*(-5) +a =0 => -10+a=0 => a=10. 
b) -ax+12=0 are ca solutie 1 <=> -a+12=0 => a=12
c) ax+a=0 are ca solutie 2 <=> 2a+a=0 => 3a=0 => a=0
1 5 1