Răspunsuri

2014-01-20T21:29:27+02:00
Arctg√3=π/3
π/3+arctgx=π/2
arctgx=π/6
x=
√3/3
da dar..tg de rad din 3 e pi/3..dar arctg de rad. din 3 nu cred ca e la fel..
tg de rad din pi/3= rad din 3
arctg de rad din 3= pi/3
aha..gata sefa.. am inteles..sar'na:*
:)):*
2014-01-20T21:31:15+02:00
Pai arctg√3=π/3
π/3+arctgx=π/2
arctgx=-π/6
S:x∈{arctg-π/6+kπ/k∈R}
S:x∈{-√3/3+kπ/k∈R}