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Cel mai inteligent răspuns!
2014-05-02T16:30:08+03:00
ΔABC,mas<A=90
sin<B=30= 1/2
sin<B=AC/BC    1/2  =AC/6  AC=6/2=3
AB²=BC²-AC²=6²-3²=36-9=27  ⇒AB=3√3

A=c1*c2/2=  AC*AB/2=  3*3√3/2=  9√3/2
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