Răspunsuri

2014-04-30T18:34:05+03:00
ΔCBD cu ∧CBD=90*cu pitagora
BD²CD²-CB²=400-100=300
BD=10√3
daca bc=1/2.CD⇒∧CDB=30*
AB||CD intersectate cu BD⇒∧CDB≡∧DBA=30*
ΔBOA dreptunghic⇒OA=AB/2=8
BO²=AB²-OA²=256-64=192
OB=8√3
in tr drept BCO CO²=CB²+BO²=100+192=292
CO=2√73
P=2√73+8√3+10+16
∧ Ce inseamna ?
unghi
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Da..multumesc mult :*
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