Răspunsuri

2014-04-30T00:48:32+03:00
A+b+c<100
{a,b,c} dp {2,5,8}
a/2=b/5=c/8=k
a/2=k⇒ a=2k
b/5=k⇒ b=5k
c/8=k⇒ c=8k
2k+5k+8k<100
15k<100        daca <100 luam o valoare care sa se imparta exact
k=90/15
k=6
atunci a=12,    b=30,    c=48
12+30+48=90<100