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2014-05-01T15:25:28+03:00
Masa moleculara : 14+5+12+48 = 79 g/mol
raport atomic N:H:C:O = 1:5:1:3
raport de masa N:H:C:O = 14:5:12:48
%N=14/79 * 100          %H=5/79 * 100          %C=12/79 * 100     %O = 48/79 * 100
1 mol NH4HCO3...........79 g
x moli NH4HCO3..........23,7 g           x = 0,3 moli NH4HCO3
1 mol NH4HCO3.......5 g H
2 moli NH4HCO3..........x g H            x = 10 g H