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2014-04-28T17:55:58+03:00
3 Fe + 4 H2O ---> Fe3O4 + 4 H2
masa molara Fe3O4=3*56+4*16=232 g/mol
%Fe = masa fier/masa molara oxid * 100=3*56/232 * 100 = 72,414% 
% O = masa oxigen/masa molara oxid * 100=16*4/232 * 100 = 27.586 %