Răspunsuri

2014-04-28T17:59:45+03:00
3 Fe + 4 H2O ----> Fe3O4 + 4 H2
masa molara = 3*56+4*16=232 g/mol
%Fe=masa fier/masa molara oxid=*100=3*56/232*100=72,414%
%O=masa oxigen/masa molara oxid=4*16/100=27,586%