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2014-04-27T14:44:22+03:00
95 g MgCl2.........2*6,022 * 10 la 23 ioni Mg (Mg cedeaza 2 electroni)
x g MgCl2.............48,176*10 la 23 ioni
x = 380 g MgCl 2
1 3 1