Răspunsuri

2014-04-27T13:52:51+03:00
3x^2-x-2=3x^2-3x+2x-2=3x(x-1)+2(x-1)=

=(x-1)(3x+2)

SAU:

Rezolvi ecuatia 3x^2-x-2=0;\ \ \Delta=25;\ \ x_1=1;\ \ \ x_2=-\dfrac23 si folosesti formula:

ax^2+bx+c=a(x-x_1)(x-x_2).  Obtii:

3x^2-x-2=3(x-1)(x+\dfrac23)=(x-1)(3x+2)