Răspunsuri

2014-04-27T11:56:04+03:00
X²+x-6=(x-2)(x+3)
x-2=0⇒x=2
x+3=0⇒x=-3
S={-3, 2}
x²-2x-8=0
(x+2)(x-4)=0
x+2=0⇒x=-2
x-4=0⇒x=4
s={-2, 4}
x²+4x-5=0
(x-1)(x+5)=0
x-1=0⇒x=1
x+5=0⇒x=-5
S={-5,1}
x²-x-12=0
(x+3)(x-4)=0
x+3=0⇒x=-3
x-4=0⇒x=4