Răspunsuri

2014-04-25T13:27:06+03:00
AD-inaltime in ΔBAD
ΔBAD- isoscel                ⇒AD- mediana ⇒BD≡DC; BD=3
ΔBDA, mD=90, mBAD=60⇒mB=30⇒th 30-60-90 AD=AB/2
Notezi AB=x⇒ AD=X/2
aplici Pitagora in ΔADB⇒AB²=BD²+AD²; 
x²=3²+x/2²
x²-x²/4=9
3x²/4=9
x²=12
x=2√3=AB
AD=√3
P=2√3+√3+6=3√3+6
P= 3(√3+2)

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