Răspunsuri

2014-04-24T16:38:01+03:00
( 2x + 4 ) (  x+2) = 0 
2x^2+4x+4x+8=0
2x^2+8x+8=0
delta=b^2-4ac
delta=8^2-4*2*8
delta=64-64
delta=0

x1=-b-radical delta/2a
x1=-8-0/4
x1=-8/4
x1=-2

x2=-b+radocal delta/2a
x2=-8+0/4
x2=-8/4
x2=-2