Răspunsuri

2014-04-24T10:55:41+03:00
(a+b+c)/3=187
a+b+c=561

2a=3b => a=3b/2
c=6b

inlocuim
3b/2+b+6b=561. Amplif cu 2 pt a avea ac numitor

3b+2b+12b=1122
17b=1122
b=66

c=6b
c=6*66
c=396

a=3b/2
a=3*66/2
a=3*33
a=99

VERIFICARE:
99+66+396/3=187?
561/3=187?
187=187 ADEVARAT
2014-04-24T10:58:03+03:00
Ma= (a+b+c)/3=187
a+b+c=561
2a=3b   b=2a/3
c=6b=   6*2a/3=  2*2a=4a

a+4a+2a/3=561  aducem la acelasi numitor
3a+12a+2a=1683
17a=1683
a=99
b=2*99/3=  2*33=66
c=4*99=396