Răspunsuri

2014-04-24T01:16:57+03:00
\dfrac a5=\dfrac b8\Rightarrow a=\dfrac{5b}{8}

3b=2c\Rightarrow c=\dfrac{3b}{2}

Inlocuim in relatia data si avem:

3\cdot\dfrac{5b}{8}+2b-\dfrac{3b}{2}=57 Aducem la acelasi numitor

15b+16b-12b=456\Rightarrow 19b=456\Rightarrow b=\dfrac{456}{19}=24

a=\dfrac{5\cdot24}{8}=15;\ \ c=\dfrac{3\cdot24}{2}=36
3 4 3