Răspunsuri

2014-04-23T17:38:29+03:00
Structura:2 atomi H,1 atom S si un atom O
Raport masic = 2:32:4*16=2:32:64=1:16:32
%H=masa hidrogen/masa molara acid * 100 = 2/98 * 100 = 2,041%
%O=masa oxigen/masa molara acid * 100 = 4*16/98 * 100 = 65,306%
%S=masa sulf/masa molara acid * 100 = 32/98 * 100 = 32,653 %

μ acid = 1+32+4*16=98g/mol