Răspunsuri

2014-04-23T16:15:53+03:00
E(x)=[(2x-8)/(x-5)(x-3)-1/(x-3)]*(x-5)(x+5)=(2x-8-x+5)/(x-5)(x-3)*(x-5)(x+5)=(x-3)/(x-3)(x-5)*(x-5)(x+5)=x+5
x²-8x+15=0  Δ=b²-4ac=64-4*1*15=4   x1,2=(-b+-√Δ)/2a=(8+-2)/2=x1=5, x2=3
x²-25=(x-5)(x+5)