Răspunsuri

2014-04-22T16:22:57+03:00
ΔABC, mas<A=90
AB²=BD*BC
AB²=BD(BD+DC)
90 000=BD²+320BD
BD²+320BD-90 000=0
BD²+320BD+25600 -115600=0
(BD+160)²-115600=0
[(BD+160)-340][(BD+160)+340]=0
(BD-180)(BD+500)=0
BD-180=0     BD+500=0
BD=180        BD=-500    BD∈N   ⇒BD=180
BC=180+320
BC=500
1 5 1