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2014-04-22T14:54:38+03:00
1m=10dm
ΔABC, mas<B=90
AC²=AB²+BC²=10²+8²=100+64=164           AC=2√41
AC=BD=2√41
A=AC*DB*sin<150/2
sin<150=sin<30+sin<60+sin<60=1/2+√3/2+√3/2= 1+2√3/2
A=2√41*2√41*  (1+2√3)/2  supra 2
A=2*41*(1+2√3) supra 2
A=41*(1+2√3)
A=41+82√3
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