Răspunsuri

2014-04-22T14:51:22+03:00
In triunghiul BCR cu <B=90³ Conform Teoremei lui Pitagora⇒CR²=BC²+BR²=24²+70²=4900+576=5476⇒CR=√5476=74 cm
Ridicam inaltimea BD perpendicular pe CR si conform teoremei catetei⇒ BC²=CD·CR⇔24²=CD·74⇒CD= \frac{576}{74}
Conform Teoremei catetei BR²=DR·CR⇔70²=DR·74⇒DR= \frac{4900}{74}
Conform Teoremei Inaltimii⇒BD²=CD·RD⇔BD²=