Răspunsuri

2014-04-22T11:45:17+03:00
Folosesti formula c=n/v
a)n=m/M=400/40=10 moli
   C=n/v=10/5=2 M
b)d=m/v->v=m/d=200/1.84=108.69
   n=m/M=196/119=1.64
    C=n/v=1.64/108.69=0.01 M
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2014-04-22T11:49:22+03:00
A)cM=nr moli/V=masa substanta/(masa molara substanta * volum)
cM=400/(40*5)=2M
b)c%=md/ms*100=196/200*100=98%
cM=c%*ro*10/masa molara H2SO4 = 98*10*1,84/98=>cM=18.4 moli/litru

sau daca nu stii formula asta folosesti varianta 2

ro = m/v=>V=m/ro=200/1,84=108,69 ml(cm cubi) = 0,10869 litri
cM=nr moli/v=masa acid/(masa molara acid * V)=196/(98*10869)=18,4 moli/litru
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