Răspunsuri

2014-04-20T14:25:27+03:00
Aducem la acelasi numitor
(x-2)(2x-3)+(x+2)(2x+3)=4(2x-3)(2x+3)
2x²-3x-4x+6+2x²+3x+4x+6=4(4x²-9)
4x²+12=16x²-36
4x²-16x²=-36-12
-8x²=-48
8x²=48
x²=6
√x²=√6
/x/=√6  ⇒x∈{-√6,√6}
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