Răspunsuri

2014-04-18T17:54:49+03:00
X²-6x+13=0

Δ=b²-4ac=36-4·1·13=-16 <0 ⇒x1,x2∉R x1=(-b+√Δ)/2a= (6+i√16)2= 3+2i , x2=3-2i

S=2x1+3x2= 2(3+2i)+3(3-2i)= 6+4i+9-6i=15-2i deci varianta : Alt raspuns :))
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