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2014-04-16T10:51:33+03:00
ΔABC, mas<A=90
AB²=BD*BC
(2√2)²=BD*(BD+DC)
8=2(2+BD)
4+2BD=8
2BD=4
BD=2
BC=2*2=4

AC²=BC²-AB²=4²-(2√2)²=16-8=8   ⇒AC=2√2   ⇒ΔABC, dreptunghic si isoscel

A=AB*AC/2=2√2*2√2/2=8/2=4