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2014-04-15T18:44:37+03:00
OM_/_(ABC)
AO inclus in (ABC)   ⇒OM_/_AO  ⇒mas<MOA=90
ΔMOA, mas<MOA=90
OM=10
AO=AC/2
AC=d=l√2=5√2
AO=5√2/2

AM²=OM²+AO²=10²+ (5√2/2)²=100 +50/4    aducem la acelasi numitor

AM²=400+50/4=450/4  ⇒AM=√450/√4=15√2/2
AM=MB=MC=MD=15√2 /2
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